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Python Variable Scope Problems: Local, Global, Nonlocal FAQ

Having trouble with Python variable scope local global nonlocal function nested scope rules? This FAQ addresses the most common scope-related problems and provides quick solutions for debugging variable access issues.

Q1: Why do I get "UnboundLocalError: local variable referenced before assignment"? #

Problem: This error occurs when Python detects that you're trying to assign to a variable later in the function, making it local, but you're trying to read it before assignment.

# This causes UnboundLocalError
counter = 0

def increment():
    print(counter)    # Error here!
    counter = counter + 1
    return counter

Solution: Use the global keyword to explicitly reference the global variable.

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Output:
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Q2: When should I use global vs nonlocal? #

Problem: Confusion about when to use each keyword for variable modification.

Answer:

  • Use global when modifying module-level variables
  • Use nonlocal when modifying variables in enclosing function scope
  • Neither is needed when just reading variables

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Output:
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Q3: Why doesn't my nested function remember the variable value? #

Problem: Variables in nested functions don't behave as expected, especially in loops.

# Problematic code
functions = []
for i in range(3):
    def func():
        return i  # All functions return the same value!
    functions.append(func)

# All print 2 (the final value of i)
for f in functions:
    print(f())

Solution: Use default arguments to capture the variable at creation time.

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Output:
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Q4: How do I modify variables in deeply nested functions? #

Problem: Need to modify variables several levels up in nested functions.

Answer: Chain nonlocal declarations or redesign using classes/return values.

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Output:
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Q5: Can I use global and nonlocal for the same variable? #

Problem: Uncertainty about combining scope modifiers.

Answer: No, you cannot use both global and nonlocal for the same variable in the same function. Choose based on where the variable is defined.

# This is invalid syntax
def invalid_function():
    global x
    nonlocal x  # SyntaxError: name 'x' is parameter and nonlocal

Correct approach:

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Output:
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Q6: Why can't I modify a list without global, but I need global to reassign it? #

Problem: Confusion about when global is required for mutable objects.

Answer: Modifying mutable objects doesn't reassign the variable, but replacing the object does.

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Output:
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Q7: How do I debug variable scope issues? #

Problem: Need strategies for identifying scope-related bugs.

Solutions:

Strategy 1: Use locals() and globals() #

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Output:
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Strategy 2: Use id() to track object identity #

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Output:
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Q8: What's the best practice for avoiding scope issues? #

Problem: Want to write clean code that avoids scope problems.

Best Practices:

1. Prefer explicit parameter passing #

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Output:
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2. Use classes for stateful operations #

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Output:
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3. Use closures carefully #

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Output:
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Common Error Messages and Quick Fixes #

ErrorCauseQuick Fix
UnboundLocalErrorReading local variable before assignmentAdd global or nonlocal declaration
NameError: name 'x' is not definedVariable doesn't exist in current scopeCheck variable definition and scope
SyntaxError: name 'x' is parameter and nonlocalConflicting scope declarationsUse either global OR nonlocal, not both

Summary #

Python variable scope local global nonlocal function nested scope rules can be tricky, but understanding these common problems helps you debug faster:

  • Use global for module-level variables
  • Use nonlocal for enclosing function variables
  • Be careful with loops and late binding
  • Prefer explicit parameters over global variables
  • Use debugging tools like locals() and globals()

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